What is the derivative of cos(x-e^x) ?

The derivative of cos(x-e^x) is -sin(x)-e^x

What is the first derivative of cos(x-e^x) ?

The first derivative of cos(x-e^x) is -sin(x)-e^x

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\frac{d}{d x} (cos (x) - e^{x})

- sin (x) - e^{x}

Solution steps

\frac{d}{d x} (cos (x) - e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (cos (x)) - \frac{d}{d x} (e^{x})

\frac{d}{d x} (cos (x)) = - sin (x)

\frac{d}{d x} (e^{x}) = e^{x}

= - sin (x) - e^{x}

\int tan^{4} (\frac{x}{2}) sec^{4} (\frac{x}{2}) d x

\int \frac{1}{9 + y ^{2}} d y

\frac{\partial}{\partial x} (sin (\frac{w}{c} x) sin (wt))

t \to 0 lim (\frac{4 e ^{t} - 4}{t})

\frac{s + 1}{( s + 2 ) ^{2}}

What is the derivative of cos(x-e^x) ?
The derivative of cos(x-e^x) is -sin(x)-e^x
What is the first derivative of cos(x-e^x) ?
The first derivative of cos(x-e^x) is -sin(x)-e^x