What is the derivative of sqrt(x)+7 ?

The derivative of sqrt(x)+7 is 1/(2sqrt(x))

What is the first derivative of sqrt(x)+7 ?

The first derivative of sqrt(x)+7 is 1/(2sqrt(x))

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\frac{d}{d x} (x + 7)

\frac{1}{2 x}

Solution steps

\frac{d}{d x} (x + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x) + \frac{d}{d x} (7)

\frac{d}{d x} (x) = \frac{1}{2 x}

\frac{d}{d x} (7) = 0

= \frac{1}{2 x} + 0

Simplify

= \frac{1}{2 x}

\int [6 cos (x) - 2 sec (x) tan (x)] d x

\int sec (u) tan (u) d u

x \to 7 + lim (\frac{∣ x - 7 ∣}{x - 7})

lo g_{3} (x^{3} + 1)

\frac{d}{d x} (\frac{x}{3})

What is the derivative of sqrt(x)+7 ?
The derivative of sqrt(x)+7 is 1/(2sqrt(x))
What is the first derivative of sqrt(x)+7 ?
The first derivative of sqrt(x)+7 is 1/(2sqrt(x))