What is the derivative of 2e^x(cos(x-sin(x))) ?

The derivative of 2e^x(cos(x-sin(x))) is -4e^xsin(x)

What is the first derivative of 2e^x(cos(x-sin(x))) ?

The first derivative of 2e^x(cos(x-sin(x))) is -4e^xsin(x)

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\frac{d}{d x} (2 e^{x} (cos (x) - sin (x)))

- 4 e^{x} sin (x)

Solution steps

\frac{d}{d x} (2 e^{x} (cos (x) - sin (x)))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (e^{x} (cos (x) - sin (x)))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = e^{x}, g = cos (x) - sin (x)

= 2 (\frac{d}{d x} (e^{x}) (cos (x) - sin (x)) + \frac{d}{d x} (cos (x) - sin (x)) e^{x})

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (cos (x) - sin (x)) = - sin (x) - cos (x)

= 2 (e^{x} (cos (x) - sin (x)) + (- sin (x) - cos (x)) e^{x})

Simplify

2 (e^{x} (cos (x) - sin (x)) + (- sin (x) - cos (x)) e^{x}) : - 4 e^{x} sin (x)

= - 4 e^{x} sin (x)

f (x) = (x - x^{2})

(y) d x + (y - x) d y = 0

x y^{^{'}} - 3 y + 12 = 0

y = \frac{5}{4 x + 1}, (1, 1)

What is the derivative of 2e^x(cos(x-sin(x))) ?
The derivative of 2e^x(cos(x-sin(x))) is -4e^xsin(x)
What is the first derivative of 2e^x(cos(x-sin(x))) ?
The first derivative of 2e^x(cos(x-sin(x))) is -4e^xsin(x)