What is the tangent of f(x)=2x^2+2x,\at x=-3 ?

The tangent of f(x)=2x^2+2x,\at x=-3 is y=-10x-18

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=2x^2+2x,\at x=-3

tangent of

f (x) = 2 x^{2} + 2 x, at x = - 3

y = - 10 x - 18

Solution steps

Find the tangent point:

(- 3, 12)

Find the slope of

f (x) = 2 x^{2} + 2 x : \frac{df ( x )}{d x} = 4 x + 2

Compute the slope of

f (x) = 2 x^{2} + 2 x

x = - 3 : m = - 10

Find the line with slope m=

- 10

and passing through

(- 3, 12) : y = - 10 x - 18

y = - 10 x - 18

\int x e - x d x

\int r^{2} sin (θ) d r

\int sin^{2} (\frac{1}{2}) x d x

(- 4, 2), (- 9, - 10)

\int \frac{1}{- v ^{2} + 1} d v

What is the tangent of f(x)=2x^2+2x,\at x=-3 ?
The tangent of f(x)=2x^2+2x,\at x=-3 is y=-10x-18