What is the integral of sin^2(1/2)x ?

The integral of sin^2(1/2)x is (sin^2(1/2)x^2)/2+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of sin^2(1/2)x

\int sin^{2} (\frac{1}{2}) x d x

\frac{sin ^{2} ( \frac{1}{2} ) x ^{2}}{2} + C

Solution steps

\int sin^{2} (\frac{1}{2}) x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= sin^{2} (\frac{1}{2}) \cdot \int x d x

Apply the Power Rule

: \frac{x ^{2}}{2}

= sin^{2} (\frac{1}{2}) \frac{x ^{2}}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{sin ^{2} ( \frac{1}{2} ) x ^{2}}{2}

Add a constant to the solution

= \frac{sin ^{2} ( \frac{1}{2} ) x ^{2}}{2} + C

(- 4, 2), (- 9, - 10)

\int \frac{1}{- v ^{2} + 1} d v

8 csc (5 x^{4} - 8 x + 6)

n = 0 \sum \infty - \frac{1}{3 ^{n}}

x \to 0 lim (\frac{1}{x ^{2} + 1})

What is the integral of sin^2(1/2)x ?
The integral of sin^2(1/2)x is (sin^2(1/2)x^2)/2+C