What is the sum from n=0 to infinity of (e/(6pi))^n ?

The sum from n=0 to infinity of (e/(6pi))^n is (6pi)/(6pi-e)

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sum from n=0 to infinity of (e/(6pi))^n

n = 0 \sum \infty (\frac{e}{6 π})^{n}

\frac{6 π}{6 π - e}

Solution steps

n = 0 \sum \infty (\frac{e}{6 π})^{n}

Apply Series Geometric Test:

\frac{6 π}{6 π - e}

= \frac{6 π}{6 π - e}

\frac{x ^{2}}{1 - x}

y^{^{''}} + 3 y^{^{'}} - 10 y = 6 e^{4 x}

\int_{0}^{2} \frac{1}{16 + x ^{2}} d x

\int \frac{x}{x - 9} d x

4 x^{2} + 2 x - 1, at x = 0

What is the sum from n=0 to infinity of (e/(6pi))^n ?
The sum from n=0 to infinity of (e/(6pi))^n is (6pi)/(6pi-e)