What is the derivative of-1/3 cos(3x) ?

The derivative of-1/3 cos(3x) is sin(3x)

What is the first derivative of-1/3 cos(3x) ?

The first derivative of-1/3 cos(3x) is sin(3x)

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\frac{d}{d x} (- \frac{1}{3} cos (3 x))

sin (3 x)

Solution steps

\frac{d}{d x} (- \frac{1}{3} cos (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{1}{3} \frac{d}{d x} (cos (3 x))

Apply the chain rule:

- sin (3 x) \frac{d}{d x} (3 x)

= - sin (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= - \frac{1}{3} (- sin (3 x) \cdot 3)

Simplify

- \frac{1}{3} (- sin (3 x) \cdot 3) : sin (3 x)

= sin (3 x)

y = ln (x^{5})

f (x) = (\frac{x + 1}{x - 1})^{7}

\frac{d}{d x} (lo g_{4} (cos (2 x)))

\frac{d}{d x} (- \frac{3}{x ^{2}} + 4 e^{2 x})

\int r^{2} + z^{2} d z

What is the derivative of-1/3 cos(3x) ?
The derivative of-1/3 cos(3x) is sin(3x)
What is the first derivative of-1/3 cos(3x) ?
The first derivative of-1/3 cos(3x) is sin(3x)