What is the derivative of-3/(x^2+4e^{2x}) ?

The derivative of-3/(x^2+4e^{2x}) is 6/(x^3)+8e^{2x}

What is the first derivative of-3/(x^2+4e^{2x}) ?

The first derivative of-3/(x^2+4e^{2x}) is 6/(x^3)+8e^{2x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (- \frac{3}{x ^{2}} + 4 e^{2 x})

\frac{6}{x ^{3}} + 8 e^{2 x}

Solution steps

\frac{d}{d x} (- \frac{3}{x ^{2}} + 4 e^{2 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (\frac{3}{x ^{2}}) + \frac{d}{d x} (4 e^{2 x})

\frac{d}{d x} (\frac{3}{x ^{2}}) = - \frac{6}{x ^{3}}

\frac{d}{d x} (4 e^{2 x}) = 8 e^{2 x}

= - (- \frac{6}{x ^{3}}) + 8 e^{2 x}

Simplify

= \frac{6}{x ^{3}} + 8 e^{2 x}

\int r^{2} + z^{2} d z

\frac{d}{d t} (2 sin (t))

f (x) = \frac{x ^{2}}{3}

\frac{\partial}{\partial y} (2 x + 3 y - 7)

\int 0.8 x + 3 d x

What is the derivative of-3/(x^2+4e^{2x}) ?
The derivative of-3/(x^2+4e^{2x}) is 6/(x^3)+8e^{2x}
What is the first derivative of-3/(x^2+4e^{2x}) ?
The first derivative of-3/(x^2+4e^{2x}) is 6/(x^3)+8e^{2x}