What is (\partial)/(\partial y)(2x+3y-7) ?

The answer to (\partial)/(\partial y)(2x+3y-7) is 3

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(\partial)/(\partial y)(2x+3y-7)

\frac{\partial}{\partial y} (2 x + 3 y - 7)

3

Solution steps

\frac{\partial}{\partial y} (2 x + 3 y - 7)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x) + \frac{\partial}{\partial y} (3 y) - \frac{\partial}{\partial y} (7)

\frac{\partial}{\partial y} (2 x) = 0

\frac{\partial}{\partial y} (3 y) = 3

\frac{\partial}{\partial y} (7) = 0

= 0 + 3 - 0

Simplify

= 3

\int 0.8 x + 3 d x

\int \frac{d}{1} (cos (2 x)) d x

n = 1 \sum \infty (1 - p)^{3 n}

x \to 1 lim (3 x^{2} - 1)

\int \frac{1}{5} e^{- \frac{x}{5}} d x

What is (\partial)/(\partial y)(2x+3y-7) ?
The answer to (\partial)/(\partial y)(2x+3y-7) is 3