What is the integral of 1 (cos(2x)) ?

The integral of 1 (cos(2x)) is d 1/2 sin(2x)+C

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integral of 1 (cos(2x))

\int \frac{d}{1} (cos (2 x)) d x

d \frac{1}{2} sin (2 x) + C

Solution steps

\int \frac{d}{1} cos (2 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= d \cdot \int cos (2 x) d x

Apply u-substitution

: \int cos (u) \frac{1}{2} d u

= d \cdot \int cos (u) \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= d \frac{1}{2} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= d \frac{1}{2} sin (u)

Substitute back

u = 2 x

= d \frac{1}{2} sin (2 x)

Add a constant to the solution

= d \frac{1}{2} sin (2 x) + C

n = 1 \sum \infty (1 - p)^{3 n}

x \to 1 lim (3 x^{2} - 1)

\int \frac{1}{5} e^{- \frac{x}{5}} d x

\int (2 + tan^{2} (x)) d x

x \to 0 + lim (L (x))

What is the integral of 1 (cos(2x)) ?
The integral of 1 (cos(2x)) is d 1/2 sin(2x)+C