What is the integral of (2+tan^2(x)) ?

The integral of (2+tan^2(x)) is tan(x)+x+C

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integral of (2+tan^2(x))

\int (2 + tan^{2} (x)) d x

tan (x) + x + C

Solution steps

\int 2 + tan^{2} (x) d x

Rewrite using trig identities

= \int sec^{2} (x) + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int sec^{2} (x) d x + \int 1 d x

\int sec^{2} (x) d x = tan (x)

\int 1 d x = x

= tan (x) + x

Add a constant to the solution

= tan (x) + x + C

x \to 0 + lim (L (x))

\frac{d ^{2} x}{d t ^{2}} + 4 x = cos (3 t)

x \to 2 lim (4 - a \cdot x)

n = 0 \sum \infty 3 x^{n}

What is the integral of (2+tan^2(x)) ?
The integral of (2+tan^2(x)) is tan(x)+x+C