What is the derivative of (3x)/(sqrt(x^2+3)) ?

The derivative of (3x)/(sqrt(x^2+3)) is 9/((x^2+3)sqrt(x^2+3))

What is the first derivative of (3x)/(sqrt(x^2+3)) ?

The first derivative of (3x)/(sqrt(x^2+3)) is 9/((x^2+3)sqrt(x^2+3))

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derivative of

\frac{3 x}{x ^{2} + 3}

\frac{9}{( x ^{2} + 3 ) x ^{2} + 3}

Solution steps

\frac{d}{d x} (\frac{3 x}{x ^{2} + 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{x}{x ^{2} + 3})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 3 \cdot \frac{\frac{d x}{d x} x ^{2} + 3 - \frac{d}{d x} ( x ^{2} + 3 ) x}{( x ^{2} + 3 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x^{2} + 3) = \frac{x}{x ^{2} + 3}

= 3 \cdot \frac{1 \cdot x ^{2} + 3 - \frac{x}{x ^{2} + 3} x}{( x ^{2} + 3 ) ^{2}}

Simplify

3 \cdot \frac{1 \cdot x ^{2} + 3 - \frac{x}{x ^{2} + 3} x}{( x ^{2} + 3 ) ^{2}} : \frac{9}{( x ^{2} + 3 ) x ^{2} + 3}

= \frac{9}{( x ^{2} + 3 ) x ^{2} + 3}

y^{^{'}} = \frac{x}{3 y}

\int \frac{6}{1 - cos ( 3 x )} d x

\frac{( x ^{2} + 4 x + 3 )}{x}

\int x 1 0^{x} d x

(\frac{9 y ^{2} - t ^{2}}{y ^{5}}) \frac{d y}{d t} + \frac{t}{2 y ^{4}} = 0

What is the derivative of (3x)/(sqrt(x^2+3)) ?
The derivative of (3x)/(sqrt(x^2+3)) is 9/((x^2+3)sqrt(x^2+3))
What is the first derivative of (3x)/(sqrt(x^2+3)) ?
The first derivative of (3x)/(sqrt(x^2+3)) is 9/((x^2+3)sqrt(x^2+3))