What is the derivative of (x^2+5x+2^7) ?

The derivative of (x^2+5x+2^7) is 7(x^2+5x+2)^6(2x+5)

What is the first derivative of (x^2+5x+2^7) ?

The first derivative of (x^2+5x+2^7) is 7(x^2+5x+2)^6(2x+5)

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\frac{d}{d x} ((x^{2} + 5 x + 2)^{7})

7 (x^{2} + 5 x + 2)^{6} (2 x + 5)

Solution steps

\frac{d}{d x} ((x^{2} + 5 x + 2)^{7})

Apply the chain rule:

7 (x^{2} + 5 x + 2)^{6} \frac{d}{d x} (x^{2} + 5 x + 2)

= 7 (x^{2} + 5 x + 2)^{6} \frac{d}{d x} (x^{2} + 5 x + 2)

\frac{d}{d x} (x^{2} + 5 x + 2) = 2 x + 5

= 7 (x^{2} + 5 x + 2)^{6} (2 x + 5)

\frac{\partial}{\partial z} (x y e^{x})

\frac{\partial}{\partial x} ((2 t - 1) (3 t - 6)^{- 1})

\int \frac{x + 1}{x} d x

\frac{d}{d x} (b y (x) (x)^{2})

\int (1 + 2 x)^{4} (2) d x

What is the derivative of (x^2+5x+2^7) ?
The derivative of (x^2+5x+2^7) is 7(x^2+5x+2)^6(2x+5)
What is the first derivative of (x^2+5x+2^7) ?
The first derivative of (x^2+5x+2^7) is 7(x^2+5x+2)^6(2x+5)