What is the solution for (dx)/(dt)-(tan(t))x=sin(t),x(0)=1 ?

The solution for (dx)/(dt)-(tan(t))x=sin(t),x(0)=1 is x=(sin^2(t))/(2cos(t))+1/(cos(t))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dx)/(dt)-(tan(t))x=sin(t),x(0)=1

\frac{d x}{d t} - (tan (t)) x = sin (t), x (0) = 1

x = \frac{sin ^{2} ( t )}{2 cos ( t )} + \frac{1}{cos ( t )}

Solution steps

\frac{d x}{d t} - (tan (t)) x = sin (t)

Solve linear ODE:

x = \frac{sin ^{2} ( t )}{2 cos ( t )} + \frac{1}{cos ( t )}

x = \frac{sin ^{2} ( t )}{2 cos ( t )} + \frac{1}{cos ( t )}

\frac{d}{d x} (x^{3} e^{- x^{2}})

\frac{d}{d x} ((5 x + 3)^{2})

y^{^{'}} + y = x e^{- x} + 1

\frac{d x}{d t} + 2 t x = 1

tan (4) x^{3}

What is the solution for (dx)/(dt)-(tan(t))x=sin(t),x(0)=1 ?
The solution for (dx)/(dt)-(tan(t))x=sin(t),x(0)=1 is x=(sin^2(t))/(2cos(t))+1/(cos(t))