What is the integral of 1/(x^{1.8)} ?

The integral of 1/(x^{1.8)} is -(1.25)/(x^{0.8)}+C

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integral of 1/(x^{1.8)}

\int \frac{1}{x ^{1.8}} d x

- \frac{1.25}{x ^{0.8}} + C

Solution steps

\int \frac{1}{x ^{1.8}} d x

Apply the Power Rule

: - \frac{1.25}{x ^{0.8}}

= - \frac{1.25}{x ^{0.8}}

Add a constant to the solution

= - \frac{1.25}{x ^{0.8}} + C

\frac{d y}{d x} - cos (x) y = \frac{1}{100} cos (x)

\int sin (x^{2}) x d x

x \to 2 lim (x - 1)

\frac{d}{d x} (\frac{2 x + 1}{x + 5} (3 x - 1))

t^{2} y^{^{''}} + 19 t y^{^{'}} + 117 y = 0

What is the integral of 1/(x^{1.8)} ?
The integral of 1/(x^{1.8)} is -(1.25)/(x^{0.8)}+C