What is area x=-5,x=3,y=2x^2+12,y=0 ?

The answer to area x=-5,x=3,y=2x^2+12,y=0 is 592/3

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area x=-5,x=3,y=2x^2+12,y=0

area

x = - 5, x = 3, y = 2 x^{2} + 12, y = 0

\frac{592}{3}

Solution steps

Apply the area formula:

\int_{- 5}^{3} 2 x^{2} + 12 d x

Solve

\int_{- 5}^{3} 2 x^{2} + 12 d x : \frac{592}{3}

The area is:

= \frac{592}{3}

\int \frac{1}{( x - 2 ) ( x - 5 )} d x

\int 6 x (4 x^{2} - 9)^{2} d x

f (x) = 3 x - 0.6 x ln (x)

x \to 2 lim (x^{2} - 8 x - 2)

\frac{\partial}{\partial x} (3 x^{2} + 2 x y - 7 y^{2})

What is area x=-5,x=3,y=2x^2+12,y=0 ?
The answer to area x=-5,x=3,y=2x^2+12,y=0 is 592/3