What is the integral of 45x^2ln(x) ?

The integral of 45x^2ln(x) is 45(1/3 x^3ln(x)-(x^3)/9)+C

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integral of 45x^2ln(x)

\int 45 x^{2} ln (x) d x

45 (\frac{1}{3} x^{3} ln (x) - \frac{x ^{3}}{9}) + C

Solution steps

\int 45 x^{2} ln (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 45 \cdot \int x^{2} ln (x) d x

Apply Integration By Parts

: \frac{1}{3} x^{3} ln (x) - \int \frac{x ^{2}}{3} d x

= 45 (\frac{1}{3} x^{3} ln (x) - \int \frac{x ^{2}}{3} d x)

\int \frac{x ^{2}}{3} d x = \frac{x ^{3}}{9}

= 45 (\frac{1}{3} x^{3} ln (x) - \frac{x ^{3}}{9})

Add a constant to the solution

= 45 (\frac{1}{3} x^{3} ln (x) - \frac{x ^{3}}{9}) + C

\frac{d}{d x} (\frac{x}{9})

f (x) = tan (\frac{1}{x})

\frac{d}{d x} (\frac{100 x}{x + y}) = 0

x \to 5 + lim (\frac{x}{x - 5})

\int_{3}^{5} \frac{1}{x ^{2} - 1} d x

What is the integral of 45x^2ln(x) ?
The integral of 45x^2ln(x) is 45(1/3 x^3ln(x)-(x^3)/9)+C