What is the derivative of 6sin(2pix) ?

The derivative of 6sin(2pix) is 12picos(2pix)

What is the first derivative of 6sin(2pix) ?

The first derivative of 6sin(2pix) is 12picos(2pix)

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\frac{d}{d x} (6 sin (2 π x))

12 π cos (2 π x)

Solution steps

\frac{d}{d x} (6 sin (2 π x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (sin (2 π x))

Apply the chain rule:

cos (2 π x) \frac{d}{d x} (2 π x)

= cos (2 π x) \frac{d}{d x} (2 π x)

\frac{d}{d x} (2 π x) = 2 π

= 6 cos (2 π x) \cdot 2 π

Simplify

= 12 π cos (2 π x)

\int 8 cos (θ) sin (θ) d θ

\frac{\partial}{\partial u} (3 cos (u))

\int_{1}^{2} w^{7} e^{w^{4}} d w

y^{^{'''}} + y^{^{''}} - y^{^{'}} - y = 0

\frac{d}{d x} (\frac{36}{( 1 + 3 x ) ^{3}})

What is the derivative of 6sin(2pix) ?
The derivative of 6sin(2pix) is 12picos(2pix)
What is the first derivative of 6sin(2pix) ?
The first derivative of 6sin(2pix) is 12picos(2pix)