What is the integral from 0 to 0.5 of 750x ?

The integral from 0 to 0.5 of 750x is 93.75

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integral from 0 to 0.5 of 750x

\int_{0}^{0.5} 750 x d x

93.75

Solution steps

\int_{0}^{0.5} 750 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 750 \cdot \int_{0}^{0.5} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{0.5}

= 750 [\frac{x ^{2}}{2}]_{0}^{0.5}

Simplify

= 750 [0.5 x^{2}]_{0}^{0.5}

Compute the boundaries:

0.125

= 750 \cdot 0.125

Simplify

= 93.75

2 e^{x} cos (x)

y^{^{'}} + (\frac{1}{x} - 1) y = - \frac{2}{x}

\frac{d}{d x} (5 (2 - x^{3})^{4})

\frac{\partial}{\partial x} (- 3 y^{5} sin (3 x))

\frac{7 s + 2}{s ^{2} + 6 s + 34}

What is the integral from 0 to 0.5 of 750x ?
The integral from 0 to 0.5 of 750x is 93.75