What is (\partial)/(\partial x)(-3y^5sin(3x)) ?

The answer to (\partial)/(\partial x)(-3y^5sin(3x)) is -9y^5cos(3x)

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(\partial)/(\partial x)(-3y^5sin(3x))

\frac{\partial}{\partial x} (- 3 y^{5} sin (3 x))

- 9 y^{5} cos (3 x)

Solution steps

\frac{\partial}{\partial x} (- 3 y^{5} sin (3 x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 y^{5} \frac{\partial}{\partial x} (sin (3 x))

Apply the chain rule:

cos (3 x) \frac{\partial}{\partial x} (3 x)

= cos (3 x) \frac{\partial}{\partial x} (3 x)

\frac{\partial}{\partial x} (3 x) = 3

= - 3 y^{5} cos (3 x) \cdot 3

Simplify

= - 9 y^{5} cos (3 x)

\frac{7 s + 2}{s ^{2} + 6 s + 34}

n \to \infty lim (e^{\frac{1}{n} l n (n)})

\frac{d}{d x} (2 x^{3} - 3)

y^{^{'}} = \frac{y}{x}, y (1) = 2

\frac{d}{d x} (\frac{2 x ^{2} - 2 x + 2}{( 2 x - 1 ) ^{2}})

What is (\partial)/(\partial x)(-3y^5sin(3x)) ?
The answer to (\partial)/(\partial x)(-3y^5sin(3x)) is -9y^5cos(3x)