What is the derivative of (6x+7(7x-8)) ?

The derivative of (6x+7(7x-8)) is 84x+1

What is the first derivative of (6x+7(7x-8)) ?

The first derivative of (6x+7(7x-8)) is 84x+1

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\frac{d}{d x} ((6 x + 7) (7 x - 8))

84 x + 1

Solution steps

\frac{d}{d x} ((6 x + 7) (7 x - 8))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 6 x + 7, g = 7 x - 8

= \frac{d}{d x} (6 x + 7) (7 x - 8) + \frac{d}{d x} (7 x - 8) (6 x + 7)

\frac{d}{d x} (6 x + 7) = 6

\frac{d}{d x} (7 x - 8) = 7

= 6 (7 x - 8) + 7 (6 x + 7)

Simplify

6 (7 x - 8) + 7 (6 x + 7) : 84 x + 1

= 84 x + 1

\int x^{2} x^{e} d x

\int 3^{5 x - 1} d x

\frac{3 d y}{d x} = y^{2}

\frac{d}{d x} (\frac{x}{8 x + 8})

x \to 9 lim (\frac{x + 8}{x + 9})

What is the derivative of (6x+7(7x-8)) ?
The derivative of (6x+7(7x-8)) is 84x+1
What is the first derivative of (6x+7(7x-8)) ?
The first derivative of (6x+7(7x-8)) is 84x+1