What is the derivative of (x-2^2(x+4)) ?

The derivative of (x-2^2(x+4)) is 3x^2-12

What is the first derivative of (x-2^2(x+4)) ?

The first derivative of (x-2^2(x+4)) is 3x^2-12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} ((x - 2)^{2} (x + 4))

3 x^{2} - 12

Solution steps

\frac{d}{d x} ((x - 2)^{2} (x + 4))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = (x - 2)^{2}, g = x + 4

= \frac{d}{d x} ((x - 2)^{2}) (x + 4) + \frac{d}{d x} (x + 4) (x - 2)^{2}

\frac{d}{d x} ((x - 2)^{2}) = 2 (x - 2)

\frac{d}{d x} (x + 4) = 1

= 2 (x - 2) (x + 4) + 1 \cdot (x - 2)^{2}

Simplify

2 (x - 2) (x + 4) + 1 \cdot (x - 2)^{2} : 3 x^{2} - 12

= 3 x^{2} - 12

(4 x (- 9)^{^{'}})^{^{'}}

4 x \cdot ln (x)

x \to - 3 lim (36 - 6 x)

\int_{- 1}^{1} \frac{4}{x} d x

\frac{\partial}{\partial x} (x^{\frac{1}{8}} \cdot y^{\frac{11}{9}})

What is the derivative of (x-2^2(x+4)) ?
The derivative of (x-2^2(x+4)) is 3x^2-12
What is the first derivative of (x-2^2(x+4)) ?
The first derivative of (x-2^2(x+4)) is 3x^2-12