en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=1-x+y-xy

Solution

y^{^{'}} = 1 - x + y - x y

Solution

y = e^{- \frac{x ^{2}}{2} + x + c_{1}} - 1

Solution steps

y^{'} (x) = 1 - x + y - x y

Solve separable ODE:

y = e^{- \frac{x ^{2}}{2} + x + c_{1}} - 1

y = e^{- \frac{x ^{2}}{2} + x + c_{1}} - 1

Popular Examples

integral of 1/((1-x)^{2/3)}

\int \frac{1}{( 1 - x ) ^{\frac{2}{3}}} d x

derivative of g(x)=3arccos(x/2)derivative of

g (x) = 3 arccos (\frac{x}{2})

sum from n=1 to infinity of (4^n)/(n+1)

n = 1 \sum \infty \frac{4 ^{n}}{n + 1}

sum from n=1 to infinity of 1/(n(n+8))

n = 1 \sum \infty \frac{1}{n ( n + 8 )}

derivative of 168(2x+5)^5 derivative of

168 (2 x + 5)^{5}

Frequently Asked Questions (FAQ)

What is the solution for y^'=1-x+y-xy ?
The solution for y^'=1-x+y-xy is y=e^{-(x^2)/2+x+c_{1}}-1