y^'=1-x+y-xy

الحلّ

y^{^{'}} = 1 - x + y - x y

y = e^{- \frac{x ^{2}}{2} + x + c_{1}} - 1

خطوات الحلّ

y^{'} (x) = 1 - x + y - x y

Solve separable ODE:

y = e^{- \frac{x ^{2}}{2} + x + c_{1}} - 1

y = e^{- \frac{x ^{2}}{2} + x + c_{1}} - 1

\int \frac{1}{( 1 - x ) ^{\frac{2}{3}}} d x

g (x) = 3 arccos (\frac{x}{2})

n = 1 \sum \infty \frac{4 ^{n}}{n + 1}

n = 1 \sum \infty \frac{1}{n ( n + 8 )}

168 (2 x + 5)^{5}