What is the derivative of sqrt(x^2-16) ?

The derivative of sqrt(x^2-16) is x/(sqrt(x^2-16))

What is the first derivative of sqrt(x^2-16) ?

The first derivative of sqrt(x^2-16) is x/(sqrt(x^2-16))

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\frac{d}{d x} (x^{2} - 16)

\frac{x}{x ^{2} - 16}

Solution steps

\frac{d}{d x} (x^{2} - 16)

Apply the chain rule:

\frac{1}{2 x ^{2} - 16} \frac{d}{d x} (x^{2} - 16)

= \frac{1}{2 x ^{2} - 16} \frac{d}{d x} (x^{2} - 16)

\frac{d}{d x} (x^{2} - 16) = 2 x

= \frac{1}{2 x ^{2} - 16} \cdot 2 x

Simplify

\frac{1}{2 x ^{2} - 16} \cdot 2 x : \frac{x}{x ^{2} - 16}

= \frac{x}{x ^{2} - 16}

\int_{- l n (4)}^{0} 63 e^{t} d t

\frac{d}{d x} (\frac{e ^{x}}{x + 2})

f (x) = (2 x^{2} - 4)^{4}

\int \frac{1}{x ^{2} + 2} d (x^{2} + 1) d x

x \to \infty lim (2 x!)

What is the derivative of sqrt(x^2-16) ?
The derivative of sqrt(x^2-16) is x/(sqrt(x^2-16))
What is the first derivative of sqrt(x^2-16) ?
The first derivative of sqrt(x^2-16) is x/(sqrt(x^2-16))