What is the derivative of f(x)=x^3+x^2 ?

The derivative of f(x)=x^3+x^2 is 3x^2+2x

What is the first derivative of f(x)=x^3+x^2 ?

The first derivative of f(x)=x^3+x^2 is 3x^2+2x

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derivative of

f (x) = x^{3} + x^{2}

3 x^{2} + 2 x

Solution steps

\frac{d}{d x} (x^{3} + x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (x^{2})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (x^{2}) = 2 x

= 3 x^{2} + 2 x

\frac{d}{d x} (\frac{1}{3} cos^{3} (x))

\int \frac{205 x}{25 - x ^{4}} d x

\frac{\partial}{\partial x} (x^{- 3} y^{- 4})

x, 0

(x + 4 y) d x + 2 x d y = 0

What is the derivative of f(x)=x^3+x^2 ?
The derivative of f(x)=x^3+x^2 is 3x^2+2x
What is the first derivative of f(x)=x^3+x^2 ?
The first derivative of f(x)=x^3+x^2 is 3x^2+2x