What is the derivative of f(x)=(x^2-1)/(x+1) ?

The derivative of f(x)=(x^2-1)/(x+1) is 1

What is the first derivative of f(x)=(x^2-1)/(x+1) ?

The first derivative of f(x)=(x^2-1)/(x+1) is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = \frac{x ^{2} - 1}{x + 1}

1

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 1}{x + 1})

Simplify

\frac{x ^{2} - 1}{x + 1} : x - 1

= \frac{d}{d x} (x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (1)

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 1 - 0

Simplify

= 1

\frac{d}{d x} (\frac{2}{5} x^{5} - 4 x^{3} + 9 x^{2} - 6 x - 2)

x \to 1 + lim (ln (x^{5} - 1))

\frac{d}{d x} ((2 x + 3) (x - 2))

arccos (\frac{x}{2})

y^{^{'}} = \frac{2 x + sec ^{2} ( x )}{2 y}, y (0) = - 3

What is the derivative of f(x)=(x^2-1)/(x+1) ?
The derivative of f(x)=(x^2-1)/(x+1) is 1
What is the first derivative of f(x)=(x^2-1)/(x+1) ?
The first derivative of f(x)=(x^2-1)/(x+1) is 1