What is the integral of 2ex+8x^3+6x ?

The integral of 2ex+8x^3+6x is ex^2+2x^4+3x^2+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 2ex+8x^3+6x

\int 2 e x + 8 x^{3} + 6 x d x

e x^{2} + 2 x^{4} + 3 x^{2} + C

Solution steps

\int 2 e x + 8 x^{3} + 6 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 e x d x + \int 8 x^{3} d x + \int 6 x d x

\int 2 e x d x = e x^{2}

\int 8 x^{3} d x = 2 x^{4}

\int 6 x d x = 3 x^{2}

= e x^{2} + 2 x^{4} + 3 x^{2}

Add a constant to the solution

= e x^{2} + 2 x^{4} + 3 x^{2} + C

\int_{0}^{1} \frac{61}{4 x - 1} d x

\frac{d}{d x} (\frac{1}{1 - \frac{2}{x}})

\frac{d}{d t} (cos (8 t))

y^{^{'}} = \frac{1}{( t \cdot y + y + t + 1 )}, y (0) = - 1

f (x) = x + 35, (1, 6)

What is the integral of 2ex+8x^3+6x ?
The integral of 2ex+8x^3+6x is ex^2+2x^4+3x^2+C