What is the d/(dt)(cos(8t)) ?

The d/(dt)(cos(8t)) is -sin(8t)*8

What is the first d/(dt)(cos(8t)) ?

The first d/(dt)(cos(8t)) is -sin(8t)*8

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\frac{d}{d t} (cos (8 t))

- sin (8 t) \cdot 8

Solution steps

\frac{d}{d t} (cos (8 t))

Apply the chain rule:

- sin (8 t) \frac{d}{d t} (8 t)

= - sin (8 t) \frac{d}{d t} (8 t)

\frac{d}{d t} (8 t) = 8

= - sin (8 t) \cdot 8

y^{^{'}} = \frac{1}{( t \cdot y + y + t + 1 )}, y (0) = - 1

f (x) = x + 35, (1, 6)

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