What is the integral of ((sqrt(x)+8)^3)/(2sqrt(x)) ?

The integral of ((sqrt(x)+8)^3)/(2sqrt(x)) is 1/4 (sqrt(x)+8)^4+C

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integral of ((sqrt(x)+8)^3)/(2sqrt(x))

\int \frac{( x + 8 ) ^{3}}{2 x} d x

\frac{1}{4} (x + 8)^{4} + C

Solution steps

\int \frac{( x + 8 ) ^{3}}{2 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{( x + 8 ) ^{3}}{x} d x

Apply u-substitution

: \int 2 u^{3} d u

= \frac{1}{2} \cdot \int 2 u^{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot 2 \cdot \int u^{3} d u

Apply the Power Rule

: \frac{u ^{4}}{4}

= \frac{1}{2} \cdot 2 \cdot \frac{u ^{4}}{4}

Substitute back

u = x + 8

= \frac{1}{2} \cdot 2 \cdot \frac{( x + 8 ) ^{4}}{4}

Simplify

\frac{1}{2} \cdot 2 \cdot \frac{( x + 8 ) ^{4}}{4} : \frac{1}{4} (x + 8)^{4}

= \frac{1}{4} (x + 8)^{4}

Add a constant to the solution

= \frac{1}{4} (x + 8)^{4} + C

f (x) = 10 x^{2}

x \to 1 lim (0)

f (x) = 3 x^{2} + 5 x

x \to 1 lim (\frac{x + 6}{x - 1})

x \to 5 + lim (\frac{∣ x - 5 ∣}{5 - x})

What is the integral of ((sqrt(x)+8)^3)/(2sqrt(x)) ?
The integral of ((sqrt(x)+8)^3)/(2sqrt(x)) is 1/4 (sqrt(x)+8)^4+C