What is the limit as x approaches 1 of (x+6)/(x-1) ?

The limit as x approaches 1 of (x+6)/(x-1) is diverges

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limit as x approaches 1 of (x+6)/(x-1)

x \to 1 lim (\frac{x + 6}{x - 1})

diverges

Solution steps

x \to 1 lim (\frac{x + 6}{x - 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (\frac{x + 6}{x - 1}) = \infty

x \to 1 - lim (\frac{x + 6}{x - 1}) = - \infty

= diverges

x \to 5 + lim (\frac{∣ x - 5 ∣}{5 - x})

\int \frac{8}{x ^{2} - 4} d x

y^{^{''}} = 3 y

y = 0, y = x^{2} - x

\int \frac{sec ( x ) + cos ( x )}{2 cos ( x )} d x

What is the limit as x approaches 1 of (x+6)/(x-1) ?
The limit as x approaches 1 of (x+6)/(x-1) is diverges