What is the solution for y^{''}=3y ?

The solution for y^{''}=3y is y=c_{1}e^{sqrt(3)t}+c_{2}e^{-sqrt(3)t}

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y^{''}=3y

y^{^{''}} = 3 y

y = c_{1} e^{3 t} + c_{2} e^{- 3 t}

Solution steps

y^{''} (t) = 3 y

Solve linear ODE:

y = c_{1} e^{3 t} + c_{2} e^{- 3 t}

y = c_{1} e^{3 t} + c_{2} e^{- 3 t}

y = 0, y = x^{2} - x

\int \frac{sec ( x ) + cos ( x )}{2 cos ( x )} d x

\int \frac{5}{x - 4} d x

3 x \frac{d y}{d x} + y = 0, y (1) = 1

(x, y) \to (in f ini t y, in f ini t y) lim (x y)

What is the solution for y^{''}=3y ?
The solution for y^{''}=3y is y=c_{1}e^{sqrt(3)t}+c_{2}e^{-sqrt(3)t}