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Popular >

area y=0,y=x^2-x

Solution

area

y = 0, y = x^{2} - x

Solution

\frac{1}{6}

+1

Decimal Notation

0.16666 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} x^{2} - x d x

Solve

\int_{0}^{1} x^{2} - x d x : \frac{1}{6}

The area is:

= \frac{1}{6}

Popular Examples

integral of (sec(x)+cos(x))/(2cos(x))

\int \frac{sec ( x ) + cos ( x )}{2 cos ( x )} d x

integral of 5/(x-4)

\int \frac{5}{x - 4} d x

3x(dy)/(dx)+y=0,y(1)=1

3 x \frac{d y}{d x} + y = 0, y (1) = 1

limit as (x,y) approaches (infinity,infinity) of xy

(x, y) \to (in f ini t y, in f ini t y) lim (x y)

tangent of y=8x+9cos(x),(0,9)tangent of

y = 8 x + 9 cos (x), (0, 9)

Frequently Asked Questions (FAQ)

What is area y=0,y=x^2-x ?
The answer to area y=0,y=x^2-x is 1/6