What is the tangent of y=8x+9cos(x),(0,9) ?

The tangent of y=8x+9cos(x),(0,9) is y=8x+9

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tangent of y=8x+9cos(x),(0,9)

tangent of

y = 8 x + 9 cos (x), (0, 9)

y = 8 x + 9

Solution steps

Find the slope of

y = 8 x + 9 cos (x) : \frac{d y}{d x} = 8 - 9 sin (x)

Compute the slope of

y = 8 x + 9 cos (x)

(0, 9) : m = 8

Find the line with slope m=

8

and passing through

(0, 9) : y = 8 x + 9

y = 8 x + 9

\int \frac{e ^{x}}{x ^{2}} d x

\frac{d}{d x} (\frac{e ^{2 x - 1}}{( x ^{2} + 5 x )})

1 + 4 - x

\frac{1}{4 y}

2 y d x + x d y = 0

What is the tangent of y=8x+9cos(x),(0,9) ?
The tangent of y=8x+9cos(x),(0,9) is y=8x+9