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Popular >

tangent of f(x)= 3/(4x+1),\at x=-1

Solution

tangent of

f (x) = \frac{3}{4 x + 1}, at x = - 1

Solution

y = - \frac{4}{3} x - \frac{7}{3}

Solution steps

Find the tangent point:

(- 1, - 1)

Find the slope of

f (x) = \frac{3}{4 x + 1} : \frac{df ( x )}{d x} = - \frac{12}{( 4 x + 1 ) ^{2}}

Compute the slope of

f (x) = \frac{3}{4 x + 1}

at

x = - 1 : m = - \frac{4}{3}

Find the line with slope m=

- \frac{4}{3}

and passing through

(- 1, - 1) : y = - \frac{4}{3} x - \frac{7}{3}

y = - \frac{4}{3} x - \frac{7}{3}

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derivative of (e^{arctan(x})/(1+x^2))

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derivative of (csc(3x)/(x^3))

\frac{d}{d x} (\frac{csc ( 3 x )}{x ^{3}})

integral of (x-4)/(x^9)

\int \frac{x - 4}{x ^{9}} d x

derivative of x^{5/3}

\frac{d}{d x} (x^{\frac{5}{3}})

laplacetransform 2te^{-5t}laplace transform

2 t e^{- 5 t}

Frequently Asked Questions (FAQ)

What is the tangent of f(x)= 3/(4x+1),\at x=-1 ?
The tangent of f(x)= 3/(4x+1),\at x=-1 is y=-4/3 x-7/3