What is laplacetransform 2te^{-5t} ?

The answer to laplacetransform 2te^{-5t} is 2/((s+5)^2)

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laplacetransform 2te^{-5t}

laplace transform

2 t e^{- 5 t}

\frac{2}{( s + 5 ) ^{2}}

Solution steps

L {2 e^{- 5 t} t}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 2 L {t e^{- 5 t}}

L {t e^{- 5 t}} : \frac{1}{( s + 5 ) ^{2}}

= 2 \cdot \frac{1}{( s + 5 ) ^{2}}

Refine

2 \frac{1}{( s + 5 ) ^{2}} : \frac{2}{( s + 5 ) ^{2}}

= \frac{2}{( s + 5 ) ^{2}}

\frac{d}{d x} (10 x - 1.86 x^{2})

\frac{\partial}{\partial x} (y^{8 x})

x \to \frac{1}{2} lim (\frac{x ^{2}}{x - 1})

y = tan^{2} (9 x)

x \frac{d y}{d x} + y = x

What is laplacetransform 2te^{-5t} ?
The answer to laplacetransform 2te^{-5t} is 2/((s+5)^2)