What is the solution for (dy)/(dx)=((x^2+3y^2))/((2xy)) ?

The solution for (dy)/(dx)=((x^2+3y^2))/((2xy)) is y=xsqrt(-1+c_{1)x},y=-xsqrt(-1+c_{1)x}

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(dy)/(dx)=((x^2+3y^2))/((2xy))

\frac{d y}{d x} = \frac{( x ^{2} + 3 y ^{2} )}{( 2 x y )}

y = x - 1 + c_{1} x, y = - x - 1 + c_{1} x

Solution steps

\frac{d y}{d x} = \frac{( x ^{2} + 3 y ^{2} )}{( 2 x y )}

Solve Bernoulli ODE:

y = x - 1 + c_{1} x, y = - x - 1 + c_{1} x

y = x - 1 + c_{1} x, y = - x - 1 + c_{1} x

\int \frac{1}{x ^{2} + a} d x

\frac{d y}{d x} = 2 + 3 + y - 2 x

\frac{d}{d x} ((2 x + 5) (3 x - 4))

sin (2 x + 2)

\int co tan (\frac{x}{3}) d x

What is the solution for (dy)/(dx)=((x^2+3y^2))/((2xy)) ?
The solution for (dy)/(dx)=((x^2+3y^2))/((2xy)) is y=xsqrt(-1+c_{1)x},y=-xsqrt(-1+c_{1)x}