What is the derivative of f(x)=3^{2x} ?

The derivative of f(x)=3^{2x} is 2ln(3)*9^x

What is the first derivative of f(x)=3^{2x} ?

The first derivative of f(x)=3^{2x} is 2ln(3)*9^x

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derivative of

f (x) = 3^{2 x}

2 ln (3) \cdot 9^{x}

Solution steps

\frac{d}{d x} (3^{2 x})

Simplify

3^{2 x} : 9^{x}

= \frac{d}{d x} (9^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 9^{x} ln (9)

Simplify

ln (9) : 2 ln (3)

= 2 ln (3) \cdot 9^{x}

(3 y^{2} - x y) d x + x^{2} d y = 0

\int 2 x^{2} 1 - x^{3} d x

\frac{\partial}{\partial x} (3 x y + y^{2})

\int (2 - 3 e^{x}) d x

\frac{\partial}{\partial x} (cos (x^{2} y^{3}))

What is the derivative of f(x)=3^{2x} ?
The derivative of f(x)=3^{2x} is 2ln(3)*9^x
What is the first derivative of f(x)=3^{2x} ?
The first derivative of f(x)=3^{2x} is 2ln(3)*9^x