What is the derivative of (3x+6/(2sqrt(x+3))) ?

The derivative of (3x+6/(2sqrt(x+3))) is (3x+12)/(4(x+3)sqrt(x+3))

What is the first derivative of (3x+6/(2sqrt(x+3))) ?

The first derivative of (3x+6/(2sqrt(x+3))) is (3x+12)/(4(x+3)sqrt(x+3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{3 x + 6}{2 x + 3})

\frac{3 x + 12}{4 ( x + 3 ) x + 3}

Solution steps

\frac{d}{d x} (\frac{3 x + 6}{2 x + 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (\frac{3 x + 6}{x + 3})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{2} \cdot \frac{\frac{d}{d x} ( 3 x + 6 ) x + 3 - \frac{d}{d x} ( x + 3 ) ( 3 x + 6 )}{( x + 3 ) ^{2}}

\frac{d}{d x} (3 x + 6) = 3

\frac{d}{d x} (x + 3) = \frac{1}{2 x + 3}

= \frac{1}{2} \cdot \frac{3 x + 3 - \frac{1}{2 x + 3} ( 3 x + 6 )}{( x + 3 ) ^{2}}

Simplify

\frac{1}{2} \cdot \frac{3 x + 3 - \frac{1}{2 x + 3} ( 3 x + 6 )}{( x + 3 ) ^{2}} : \frac{3 x + 12}{4 ( x + 3 ) x + 3}

= \frac{3 x + 12}{4 ( x + 3 ) x + 3}

y^{^{''}} + 80 y^{^{'}} + 1200 y = 0

\frac{\partial}{\partial x} (4 cos (3 x))

\int 2 x (4 x - 3)^{3} d x

\frac{2}{( 3 x ^{2} + 7 ) ^{2}}

What is the derivative of (3x+6/(2sqrt(x+3))) ?
The derivative of (3x+6/(2sqrt(x+3))) is (3x+12)/(4(x+3)sqrt(x+3))
What is the first derivative of (3x+6/(2sqrt(x+3))) ?
The first derivative of (3x+6/(2sqrt(x+3))) is (3x+12)/(4(x+3)sqrt(x+3))