What is the tangent of (4x)/(x-3),\at x=5 ?

The tangent of (4x)/(x-3),\at x=5 is y=-3x+25

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tangent of (4x)/(x-3),\at x=5

tangent of

\frac{4 x}{x - 3}, at x = 5

y = - 3 x + 25

Solution steps

Find the tangent point:

(5, 10)

Find the slope of

y = \frac{4 x}{x - 3} : \frac{d y}{d x} = - \frac{12}{( x - 3 ) ^{2}}

Compute the slope of

y = \frac{4 x}{x - 3}

x = 5 : m = - 3

Find the line with slope m=

- 3

and passing through

(5, 10) : y = - 3 x + 25

y = - 3 x + 25

f (x) = \frac{x ^{3}}{3} + x^{2} + 4 x - 10

y = 10 x - x^{2}, (5, 26)

\int \frac{1}{x - ln ^{2} ( x ) + ln ( x ) + 3} d x

\frac{d}{d t} (2 e^{t} + 2 e^{2 t})

\int \frac{2 x + 5}{9 - x ^{2}} d x

What is the tangent of (4x)/(x-3),\at x=5 ?
The tangent of (4x)/(x-3),\at x=5 is y=-3x+25