What is the integral of (-2sec^2(x)) ?

The integral of (-2sec^2(x)) is -2tan(x)+C

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integral of (-2sec^2(x))

\int (- 2 sec^{2} (x)) d x

- 2 tan (x) + C

Solution steps

\int - 2 sec^{2} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \int sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= - 2 tan (x)

Add a constant to the solution

= - 2 tan (x) + C

\int_{1}^{2} \frac{2}{x ^{3}} d x

9 (t + 1) \frac{d y}{d t} - 8 y = 8 t

y = \frac{1}{x} + cos (2 x)

x \to 4 + lim (16 - x^{2})

What is the integral of (-2sec^2(x)) ?
The integral of (-2sec^2(x)) is -2tan(x)+C