What is the integral from 0 to 1 of (53)/(x^5) ?

The integral from 0 to 1 of (53)/(x^5) is diverges

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integral from 0 to 1 of (53)/(x^5)

\int_{0}^{1} \frac{53}{x ^{5}} d x

diverges

Solution steps

\int_{0}^{1} \frac{53}{x ^{5}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 53 \cdot \int_{0}^{1} \frac{1}{x ^{5}} d x

Apply the Power Rule

: [- \frac{1}{4 x ^{4}}]_{0}^{1}

= 53 [- \frac{1}{4 x ^{4}}]_{0}^{1}

Compute the boundaries:

diverges

= diverges

\frac{\partial}{\partial x} (- \frac{x}{y})

\int_{- 1}^{1} (2 x - 1)^{2} d x

\int sin^{2} (14 x) d x

\frac{d y}{d x} = - 5 - 5 x + y

2 y d x + x^{2} d y = - d x

What is the integral from 0 to 1 of (53)/(x^5) ?
The integral from 0 to 1 of (53)/(x^5) is diverges