What is the solution for 2ydx+x^2dy=-dx ?

The solution for 2ydx+x^2dy=-dx is y=(e^{(2-2c_{1}x)/x})/(2)-1/2

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2ydx+x^2dy=-dx

2 y d x + x^{2} d y = - d x

y = \frac{e ^{\frac{2 - 2 c _{1} x}{x}}}{2} - \frac{1}{2}

Solution steps

2 y d x + x^{2} d y = - d x

Solve separable ODE:

y = \frac{e ^{\frac{2 - 2 c _{1} x}{x}}}{2} - \frac{1}{2}

y = \frac{e ^{\frac{2 - 2 c _{1} x}{x}}}{2} - \frac{1}{2}

\int x^{2} 3^{5 x^{3} + 1} d x

\int_{0}^{\frac{1}{2}} x^{2} d x

\int 2 y d y

\frac{\partial}{\partial x} ((x - 5)^{\frac{1}{4}} y^{\frac{1}{4}})

f (x) = e^{x} sin (x)

What is the solution for 2ydx+x^2dy=-dx ?
The solution for 2ydx+x^2dy=-dx is y=(e^{(2-2c_{1}x)/x})/(2)-1/2