What is the integral from 0 to 1/2 of x^2 ?

The integral from 0 to 1/2 of x^2 is 1/24

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integral from 0 to 1/2 of x^2

\int_{0}^{\frac{1}{2}} x^{2} d x

\frac{1}{24}

Solution steps

\int_{0}^{\frac{1}{2}} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{\frac{1}{2}}

= [\frac{x ^{3}}{3}]_{0}^{\frac{1}{2}}

Compute the boundaries:

\frac{1}{24}

= \frac{1}{24}

\int 2 y d y

\frac{\partial}{\partial x} ((x - 5)^{\frac{1}{4}} y^{\frac{1}{4}})

f (x) = e^{x} sin (x)

x \to 1 lim (x^{2} + 3)

f (x) = x^{3} - 1, at x = 1

What is the integral from 0 to 1/2 of x^2 ?
The integral from 0 to 1/2 of x^2 is 1/24