What is the integral of sqrt(2y) ?

The integral of sqrt(2y) is sqrt(2)ysqrt(y)-(sqrt(2))/3 y^{3/2}+C

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integral of sqrt(2y)

\int 2 y d y

2 y y - \frac{2}{3} y^{\frac{3}{2}} + C

Solution steps

\int 2 y d y

Apply Integration By Parts

: 2 y y - \int \frac{y}{2} d y

= 2 y y - \int \frac{y}{2} d y

\int \frac{y}{2} d y = \frac{2}{3} y^{\frac{3}{2}}

= 2 y y - \frac{2}{3} y^{\frac{3}{2}}

Add a constant to the solution

= 2 y y - \frac{2}{3} y^{\frac{3}{2}} + C

\frac{\partial}{\partial x} ((x - 5)^{\frac{1}{4}} y^{\frac{1}{4}})

f (x) = e^{x} sin (x)

x \to 1 lim (x^{2} + 3)

f (x) = x^{3} - 1, at x = 1

\frac{d}{d x} (a^{2} - x^{2} + a arcsin (\frac{x}{a}))

What is the integral of sqrt(2y) ?
The integral of sqrt(2y) is sqrt(2)ysqrt(y)-(sqrt(2))/3 y^{3/2}+C