What is the tangent of x^2-2x+1 ?

The tangent of x^2-2x+1 is y=(2a_{0}-2)x-a_{0}^2+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of x^2-2x+1

tangent of

x^{2} - 2 x + 1

y = (2 a_{0} - 2) x - a_{0}^{2} + 1

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, a_{0}^{2} - 2 a_{0} + 1)

Find the slope of

y = x^{2} - 2 x + 1 : \frac{d y}{d x} = 2 x - 2

Compute the slope of

y = x^{2} - 2 x + 1

x = a_{0} : m = 2 a_{0} - 2

Find the line with slope m=

2 a_{0} - 2

and passing through

(a_{0}, a_{0}^{2} - 2 a_{0} + 1) : y = (2 a_{0} - 2) x - a_{0}^{2} + 1

y = (2 a_{0} - 2) x - a_{0}^{2} + 1

x \to 0 + lim (\frac{5}{x ^{2}})

(x + y)^{2} d x + (2 x y + x^{2} - 8) d y = 0

f (x) = 3 x^{2} + 5 x - \frac{1}{x ^{2}} + e^{2}

x \to 0 lim (\frac{3 x + 1}{7 x})

x^{3}, at x = 2

What is the tangent of x^2-2x+1 ?
The tangent of x^2-2x+1 is y=(2a_{0}-2)x-a_{0}^2+1