What is the derivative of 5x^2+4x ?

The derivative of 5x^2+4x is 10x+4

What is the first derivative of 5x^2+4x ?

The first derivative of 5x^2+4x is 10x+4

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\frac{d}{d x} (5 x^{2} + 4 x)

10 x + 4

Solution steps

\frac{d}{d x} (5 x^{2} + 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 x^{2}) + \frac{d}{d x} (4 x)

\frac{d}{d x} (5 x^{2}) = 10 x

\frac{d}{d x} (4 x) = 4

= 10 x + 4

\frac{d}{d x} (2^{10 x})

\int x^{3} 256 - x^{2} d x

\frac{d}{d x} (cos (\frac{x}{3}) sin (x))

\int \frac{tan ( x )}{tan ^{2} ( x ) + 1} d x

\int \frac{8}{x ^{2} x ^{2} + 36} d x

What is the derivative of 5x^2+4x ?
The derivative of 5x^2+4x is 10x+4
What is the first derivative of 5x^2+4x ?
The first derivative of 5x^2+4x is 10x+4