What is the derivative of 2^{10x} ?

The derivative of 2^{10x} is 5ln(2)*2^{10x+1}

What is the first derivative of 2^{10x} ?

The first derivative of 2^{10x} is 5ln(2)*2^{10x+1}

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\frac{d}{d x} (2^{10 x})

5 ln (2) \cdot 2^{10 x + 1}

Solution steps

\frac{d}{d x} (2^{10 x})

Simplify

2^{10 x} : 102 4^{x}

= \frac{d}{d x} (102 4^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 102 4^{x} ln (1024)

Simplify

102 4^{x} ln (1024) : 5 ln (2) \cdot 2^{10 x + 1}

= 5 ln (2) \cdot 2^{10 x + 1}

\int x^{3} 256 - x^{2} d x

\frac{d}{d x} (cos (\frac{x}{3}) sin (x))

\int \frac{tan ( x )}{tan ^{2} ( x ) + 1} d x

\int \frac{8}{x ^{2} x ^{2} + 36} d x

\frac{d}{d t} (\frac{1}{2 t})

What is the derivative of 2^{10x} ?
The derivative of 2^{10x} is 5ln(2)*2^{10x+1}
What is the first derivative of 2^{10x} ?
The first derivative of 2^{10x} is 5ln(2)*2^{10x+1}