What is the d/(dt)(1/(2sqrt(t))) ?

The d/(dt)(1/(2sqrt(t))) is -1/(4t^{3/2)}

What is the first d/(dt)(1/(2sqrt(t))) ?

The first d/(dt)(1/(2sqrt(t))) is -1/(4t^{3/2)}

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\frac{d}{d t} (\frac{1}{2 t})

- \frac{1}{4 t ^{\frac{3}{2}}}

Solution steps

\frac{d}{d t} (\frac{1}{2 t})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d t} (\frac{1}{t})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{2} \frac{d}{d t} (t^{- \frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{2} (- \frac{1}{2} t^{- \frac{1}{2} - 1})

Simplify

\frac{1}{2} (- \frac{1}{2} t^{- \frac{1}{2} - 1}) : - \frac{1}{4 t ^{\frac{3}{2}}}

= - \frac{1}{4 t ^{\frac{3}{2}}}

ln (x^{10})

y = 3 x (x + 2)^{3}

\frac{\partial}{\partial x} (- 3 x^{2} + 3)

\int - 2 cos (6 x) d x

f (x) = 8 x^{15} - 6 x^{3} + 1

What is the d/(dt)(1/(2sqrt(t))) ?
The d/(dt)(1/(2sqrt(t))) is -1/(4t^{3/2)}
What is the first d/(dt)(1/(2sqrt(t))) ?
The first d/(dt)(1/(2sqrt(t))) is -1/(4t^{3/2)}