What is (\partial)/(\partial x)(-3x^2+3) ?

The answer to (\partial)/(\partial x)(-3x^2+3) is -6x

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(\partial)/(\partial x)(-3x^2+3)

\frac{\partial}{\partial x} (- 3 x^{2} + 3)

- 6 x

Solution steps

\frac{\partial}{\partial x} (- 3 x^{2} + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (3 x^{2}) + \frac{\partial}{\partial x} (3)

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (3) = 0

= - 6 x + 0

Simplify

= - 6 x

\int - 2 cos (6 x) d x

f (x) = 8 x^{15} - 6 x^{3} + 1

\frac{d y}{d t} = y^{2} - y

x^{3} - 10 x, 15 x

y^{^{'''}} + y^{^{''}} - 4 y^{^{'}} - 4 y = 0

What is (\partial)/(\partial x)(-3x^2+3) ?
The answer to (\partial)/(\partial x)(-3x^2+3) is -6x