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Popular >

area x=y^2-4,x=4

Solution

area

x = y^{2} - 4, x = 4

Solution

\frac{64 2}{3}

+1

Solution steps

Isolate

y

for

x = y^{2} - 4 : y = x + 4, y = - x + 4

Apply the area formula:

\int_{- 4}^{4} 2 x + 4 d x

Solve

\int_{- 4}^{4} 2 x + 4 d x : \frac{64 2}{3}

The area is:

= \frac{64 2}{3}

Popular Examples

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\frac{d}{d x} (1 - 2 x^{3})

integral of e^xsin(nx)

\int e^{x} sin (n x) d x

y^{''}+5y^'+6y=12

y^{^{''}} + 5 y^{^{'}} + 6 y = 12

derivative of f(x)=2x^3-5x^2+6 derivative of

f (x) = 2 x^{3} - 5 x^{2} + 6

integral from-1 to 1 of x^2-2-e^x

\int_{- 1}^{1} x^{2} - 2 - e^{x} d x

Frequently Asked Questions (FAQ)

What is area x=y^2-4,x=4 ?
The answer to area x=y^2-4,x=4 is (64sqrt(2))/3